Question 334905
I assume you mean 10 P 4 (where the P is elevated above the two numbers). I'm going to denote it as P(10, 4)



P(10,4) = (10!)/(10-4)! = (10!)/(6!) = (10*9*8*7*6!)/(6!) = 10*9*8*7 = 90*56 = 5040



So P(10, 4) = 5040



See this <a href="http://www.algebra.com/algebra/homework/Probability-and-statistics/NPR-NCR.solver">solver</a> for more help with permutations.