Question 334884
Complete the square,
{{{y^2 + 4y + 16 - 12x = 0}}}
{{{(y^2+4y+4)-12x+12=0}}}
{{{12x=(y+2)^2+12}}}
{{{x=(y+2)^2/12+1}}}
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{{{drawing(300,300, -2,16,-16,14, grid(1),blue(line(-20,-2,20,-2)),circle(1,-2,.4),graph(300,300, -2,16,-16,14,-2+sqrt(12x-12)),graph(300,300, -2,16,-16,14, -2-sqrt(12x-12)))}}}