Question 334856
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Your first equation is spot on:  *[tex \LARGE y\ =\ 3x\ +\ 3]


But your second one has a problem.  Since today the son is *[tex \LARGE x] years old and the father is *[tex \LARGE y] years old, in three years the son will be *[tex \LARGE x\ +\ 3] and the father *[tex \LARGE y\ +\ 3]


Then, according to the second condition:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ +\ 3\ =\ 2(x\ +\ 3)\ +\ 10]


Now add -3 to both sides of the second equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 2(x\ +\ 3)\ +\ 7]


Now you have *[tex \LARGE y] equal to two different things.  Set them equal to each other:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ +\ 3\ =\ 2(x\ +\ 3)\ +\ 7]


And solve for *[tex \LARGE x]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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