Question 334875
{{{((2x^3y^3z)/(3y^2z^3))^4=(2x^3y^3z)^4/(3y^2z^3)^4}}}
{{{((2x^3y^3z)/(3y^2z^3))^4=(16x^12y^12z^4)/(81y^8z^12)}}}
{{{((2x^3y^3z)/(3y^2z^3))^4=(16/81)x^(12)y^(12-8)z^(4-12)}}}
{{{((2x^3y^3z)/(3y^2z^3))^4=(16/81)x^(12)y^(4)z^(-8)}}}
{{{((2x^3y^3z)/(3y^2z^3))^4=(16x^12*y^(4))/(81z^8))}}}