Question 334850
Assume fluorescent lamps made by a manufacturer have a 
probability of 0.05 of being inoperable when new.
probability of 0.95 of being operable when new.
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A person purchases 8 of the lamps for home use. 
a) What is the probability that exactly one lamp is inoperable of the eight?
P(x = 1) = 8C1*(0.05)*(0.95)^7 = 0.2793
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b) What is the probability that all eight lamps are functional?
P(x = 0) = 8C0*(0.05)^0*(0.95)^8 = 0.95^8 = 0.6634
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c) Determine the probability that one or more lamps are not operable?
P(1<= not operable <=8) = 1-P(x=0 not operable) = 1-0.6634 = 0.3366
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d) Plot the probability that one or more lamps are not operable.
That is the same question as "c".
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Cheers,
Stan H.