Question 334845
if the square box is 20 feet from corner to corner what would be the dimensions of the square in sq yds


20 feet is the diagonal (hypotenuse) measurement of the square box
use Pythagorean Theorem
a^2 + b^2 = c^2, since square a = b, so 2a^2 = c^2, and c = 20 feet


2a^2 = 20^2 = 400
a^2 = 200 square feet, this is area of the square
a = 100 * 2 = 10sqrt(2) feet this is the length of a side of the square


1 yard = 3 feet


10sqrt(2) feet * 1/3 * yards/feet = (10/3)sqrt(2) yards per side of the square


area of square in square yards (sq yds) is then:


(10/3)sqrt(2) * (10/3)sqrt(2) = (100/9) * 2 = 200/9 sq yds


or approximately 22.2 sq yds rounded to nearest tenth