Question 334838
{{{f(x) = x^2 -x + 2}}}
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{{{f(-x) = (-x)^2 -(-x) + 2}}}
{{{f(-x) = x^2 +x + 2}}}
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If the function is even, then {{{f(x)=f(-x)}}} or {{{f(x)-f(-x)=0}}}
If the function is odd, then {{{f(x)=-f(-x)}}} of {{{f(x)+f(-x)=0}}}
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In this case, 
{{{f(x)-f(-x)=-2x}}}
{{{f(x)+f(-x)=2x^2+4}}}
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Neither.