Question 334803
{{{(p^2qr^3)/(4p^(-1)q^2r^(-1))^2}}}
<pre><b>
To remove the parentheses, first make sure every factor
inside the parentheses has its exponents showing, so we'll
even put a 1 exponent for the 4, since it's a factor inside
the parentheses:

{{{(p^2qr^3)/(4^1p^(-1)q^2r^(-1))^2}}}

Remove the parentheses on the bottom by multiplying every
exponent inside the parentheses by the exponent outside the
parentheses:

{{{(p^2qr^3)/(4^((1*2))p^((-1*2))q^(2*2)r^((-1*2)))}}}

{{{(p^2qr^3)/(4^2p^(-2)q^4r^(-2))}}}

Get rid of the negative exponents (in red)

{{{(p^2qr^3)/(4^2p^(red(-2))q^4r^(red(-2)))}}}

by moving the factors from the bottom to the top and 
changing the sign of their exponents to positive:

{{{(p^2qr^3p^red(2)r^red(2))/(4^2q^4)}}}

Now we 
1. add the exponents of {{{p}}} in the top {{{2+2=4}}}
2. add the exponents of {{{r}}} in the top {{{3+2=5}}}
3. do the exponent {{{4^2=16}}}

{{{(p^4qr^5)/(16q^4)}}}

Give the {{{q}}} in the top the exponent 1:

{{{(p^4q^1r^5)/(16q^4)}}}

Subtract the exponents of q, larger minus smaller, getting {{{4-1 = 3}}}
putting the result {{{q^3}}} in the bottom because the larger exponent
{{{4}}} was in the bottom.  (Eliminate q from the top, of course)

{{{(p^4r^5)/(16q^3)}}}

That's as far as it will simplify.

Edwin