Question 334640
<font face="Garamond" size="+2">


If *[tex \Large x\ =\ \alpha] is a solution of the quadratic equation *[tex \Large ax^2\ +\ bx\ +\ c\ =\ 0], then *[tex \Large (x\ -\ \alpha)] is a factor of *[tex \Large ax^2\ +\ bx\ +\ c].  You have two solutions, so you can write the two factors of your quadratic polynomial.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
</font>