Question 334331
John drove to a distant city in 5 hours.
 When he returned, there was less traffic and the trip took only 3 hours.
 If John averaged 26 mph faster on the return trip, how fast did he drive each way? 
:
We don't know the distance of the trips, but we know they are equal.
:
Let s = speed to the city
then
(s+26 = return speed
:
Write a distance equation: dist = time * speed
:
To dist = return dist
5s = 3(s+26)
5s = 3s + 78
5s - 3s = 78
2s = 78
s = {{{78/2}}}
s = 39 mph to the city
and
39 + 26 = 65 mph back
;
;
We can confirm our solution by finding the distances now
5*39 = 195 mi
3*65 = 195 mi also
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Pretty simple, right?