Question 334497
3 number combination such that 
One number is odd. 
One number is a multiple of 5. 
One number is the day of the month of Kyle's birthday. 
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Process of elimination
eliminate choice B, since it has two odd numbers
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multiples of 5, end in 5 or 0, but since one number has to be odd while another a multiple of 5, that means only those ending in 0 qualify, therefore, eliminate choice C
also eliminate choice D, since there would be two multiples of 5
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that leave choice A and E, but since the third critiria states that it has to be a day of the month, eliminate choice E since 34 is too high for a day of the month
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Answer: choice A