Question 334442
You need to rationalize the denominator
{{{(2i-5)/(i+1)}}}
{{{((2i-5)(i-1))/((i+1)(i-1))}}}
{{{(2i^2 - 2i - 5i +5)/(i^2 -1)}}}
{{{(-2 -7i +5)/(-1 -1)}}}
{{{(3-7i)/(-2)}}}
{{{-(3-7i)/2}}}
{{{(-3/2) + (7i/2)}}}