Question 334436
let the number be x, & y
..
product =10
xy=10
y= 10/x
x-y=3
..
plug value of y in second equation
{{{x-(10/x)=3}}}
{{{(x^2-10)/x =3}}}
{{{x^2-10= 3x}}}
x^2-3x-10=0
x^2-5x+2x-10=0
x(x-5)+2(x-5)=0
(x-5)(x+2)=0
x= 5 OR -2
x=5, y=2
x=-2, y=-5