Question 334376
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Functions containing a radical with an even index (square root, 4th root, etc.) must restrict the domain so that the value under the radical is non-negative.


Functions with a denominator must restrict the domain so that then denominator cannot go to zero.


Note that your second problem has a denominator that has no real zeros, hence the domain is all real numbers.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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