Question 334246
{{{((2r+5)/5)-((3r+1)/2)=((7-r)/2)}}}
Multiply by 10 to get rid of the denominators; results:
2(2r+5) - 5(3r+1) = 5(7-r)
:
4r + 10 - 15r - 5 = 35 - 5r
Combine the r's on the left, numbers on the right
4r - 15r + 5r = 35 - 10 + 5
:
-6r = 30
r = {{{30/(-6)}}}
r = -5
;
:
Check solution in original equation
{{{((2(-5)+5)/5)-((3(-5)+1)/2)=((7-(-5))/2)}}}
{{{((-10+5)/5)-((-15+1)/2)=((7+5)/2)}}}
{{{(-5)/5}}} - {{{(-14)/2}}} = {{{12/2}}}
-1 + 7 = 6