Question 334167
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Let *[tex \Large x] represent one leg of the triangle.  Let *[tex \Large y] represent the other leg.  Then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 15\sin(25^\circ)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 15\cos(25^\circ)]


I'll leave you alone to spend some quality time with your calculator.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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