Question 334125
let A=area of triangle
let B=base of triangle
let h=height of triangle
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therefore A=(1/2)*B*h
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Given B=(1/3)*h  and A=24
find h
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A=(1/2)*B*h; therefore 24=(1/2)*((1/3)*h)*h
24=(1/6)*h^2
24*(6)=h^2
144=h^2
12=h