Question 334005
<pre><b>
The answer could not use {{{2^8}}} or any power of 3, 5, 6, or 8 higher than the
power 2, since that would result in a value over 100 even before adding c.

So the value of the first term {{{a^b}}} could at most be one of these

{{{2^6=64}}}, {{{3^2=9}}}, {{{5^2=25}}}, {{{6^2=36}}}, or {{{8^2=64}}}

So the most we could get for {{{a^b}}} is 64.  So the answer is between using
{{{2^6}}} and {{{8^2}}}.  However if we used {{{8^2}}} for the 64, the largest number 8 
would not be available for c to add to it, whereas if we use {{{2^6}}}, we can
add the largest number 8 to that.  Thus the answer is:

{{{2^6+8=72}}} 

Edwin</pre>