Question 334055
{{{(x+2)/3=2/X}}}
{{{x(x+2)=3*2}}}
{{{x^2+2x=6}}}
{{{x^2+2x-6)=0}}}
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use quadratic formula to find the roots x1,x2
a=1,b=2,c=-6
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{{{x1= (-2+sqrt(4+24))/2}}}
x1=(-1 +sqrt28/2)
= 1.64575131
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x2=(-1 -sqrt28/2)
x2=-3.64575131