Question 333898
Simplify the radical expression: 
Square root of 108 divided by the square root of 2q to the 6th power 
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Separate the perfect square factors from the others.
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= sqrt[36/q^6]*sqrt[3/2]
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= (6/q^2)sqrt(3/2)
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= (6/q^2)(sqrt(6)/2)
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= (3/q^2)sqrt(6)
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Cheers,
Stan H.
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