Question 333861
let log k 2=11/9. find log 8 k.
---------------------
logk(2)=11/9
---
k^(11/9) = 2
k = 2^(9/11)
---------------------------
log8(k) = [log(k)]/[log(8)]
-----
= log(2^(9/11))/log(8)
-----
Take the log base 2 of numerator and denominator to get:
---
= (9/11)/3
= 3/11
==================
Cheers,
Stan H.