Question 38325
Okay from
(6xy^2/7y^3)/(15x^2y/5x^2)
Let us invert the second fraction, then we cancel wherever we can in order to simplify...so
(6xy^2/7y^3) * (5x^2/15x^2y) = 
(6x / 7y) * (1 / 3y) =
6x / 21y^2 =
2x / 7y^2