Question 333674
Sixteen liters of an ideal gas at a temperature of 500 kelvins has a pressure of 100 newtons per square meter. 
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Volume = k[t/p]
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Find "k":
16 = k[500/100]
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k = 16/5
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Equation:
V = (16/5)[t/p]
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If the volume were increased to 20 liters and the temperature reduced to 400 kelvins, what would be the pressure?
20 = (16/5)[400/p]
pressure = (16/5)[500/20]
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Pressure = 16 neutons per sq. meter
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Cheers,
Stan H.
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