Question 333657
{{{log(3,(1/81))=log(10,(1/81))/log(10,(3))=-1.90848501887864/0.47712125471967=-4}}} (the last figure is the result of rounding)



Alternatively, {{{log(3,(1/81))=ln(1/81)/ln(3)=-4.39444915467243/1.0986122886681=-4}}} (the last figure is the result of rounding)



Either way, {{{log(3,(1/81))=-4}}}