Question 333645


{{{(v-4)^2-48=0}}} Start with the given equation.



{{{(v-4)^2=0+48}}}Add {{{48}}} to both sides.



{{{(v-4)^2=48}}} Combine like terms.



{{{x-4=""+-sqrt(48)}}} Take the square root of both sides.



{{{v-4=sqrt(48)}}} or {{{v-4=-sqrt(48)}}} Break up the "plus/minus" to form two equations.



{{{v-4=4*sqrt(3)}}} or {{{v-4=-4*sqrt(3)}}}  Simplify the square root.



{{{v=4+4*sqrt(3)}}} or {{{v=4-4*sqrt(3)}}} Add {{{4}}} to both sides.



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Answer:



So the solutions are {{{v=4+4*sqrt(3)}}} or {{{v=4-4*sqrt(3)}}}.