Question 333436
Let {{{m}}} = Mother's age
Let {{{d}}} = Daughter's age
Let {{{s}}} = Son's age
given:
{{{m = 8d}}}
{{{m = 4s}}}
{{{s = d + 4}}}
This is 3 equations and 3 unknowns, so it's solvable
By substitution:
{{{m = 4*(d + 4)}}}
{{{m = 4d + 16}}}
Again, by substitution:
{{{8d = 4d + 16}}}
{{{4d = 16}}}
{{{d = 4}}}
and, since,
{{{m = 8d}}}
{{{m = 8*4}}}
{{{m = 32}}}
also,
{{{s = d + 4}}}
{{{s = 4 + 4}}}
{{{s = 8}}}
The Mother is 32, the Daughter is 4, and the Son is 8