Question 333392
<font face="Garamond" size="+2">


I think you are trying to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{4x}{3}\ +\ \frac{6}{4}\ +\ \frac{3x\ -\ 2}{2}]


But that raises the issue of what you mean by "solve."  Solve, in its ordinary sense means to find a solution set for an equation or an inequality.  You have neither, and so you can't actually "solve" this.  Now, if you made a little typo and that plus sign between the last two terms was supposed to be an equals sign, then that is another story, but I can only go on what you actually wrote.


Be that as it may, you can simplify your expression.


Your first step was a correct one, so let's go there first:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{4x}{3}\ +\ \frac{3}{2}\ +\ \frac{3x\ -\ 2}{2}]


The LCM of 2 and 3 is 6, so we choose 6 for a common denominator.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{4x}{3}\,\cdot\,\frac{2}{2}\ +\ \frac{3}{2}\,\cdot\,\frac{3}{3}\ +\ \frac{3x\ -\ 2}{2}\,\cdot\,\frac{3}{3}\ =\ \frac{8x\ +\ 9\ + 9x\ -\ 6}{6}\ =\ \frac{17x\ +\ 3}{6}] 


Write back if I'm right about that possible typo.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
</font>