Question 333079
cot(t) =1/3  is the same as tan(t)=3
therefore
tan(t)=3 can be solved as t= Arctan(3)=71.565-/+n*180 (note 71.565 is in quadrant I and you want to be in quadrant III)
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since the domain is restricted to  &#960; < t < 3&#960;/2
This puts you in quadrant III where both x and y are negative.
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so the answer is
t= Arctan(3)=71.565-/+180=251.565 (or -108.435)