Question 333040
x^2 - 3x - 15 = -5

=> x^2 - 3x - 10 = 0

=> x^2 - 5x + 2x - 10 = 0

=> x(x-5)+2(x-5)=0

=> (x-5)(x+2)=0

so x = 5 , -2



x^2 - 17x = -10x - 6 

x^2 - 7x + 6 = 0

=> x^2 - x - 6x + 6 = 0

=> x(x-1)-6(x-1)=0

=> (x-1)(x-6)=0

so x = 1, 6