Question 333021
what is the slope of 
{{{5/x + 3/y=4}}}
{{{5(-1)x^-2*dx + 3(-1)y^-2*dy = 0}}}
{{{5dx/x^2 + 3dy/y^2 = 0}}}
{{{slope = dy/dx = -5y^2/3x^2}}}
--------------------------
The slope perpendicular is the negative inverse
= {{{slope = -dx/dy = 3x^2/5y^2}}}