Question 332883
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The equation of a circle with center at *[tex \Large (h, k)] and radius *[tex \Large r] is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ -\ h)^2\ +\ (y\ -\ k)^2\ =\ r^2]


Rewrite your equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ -\ 0)^2\ +\ (y\ -\ 0)^2\ =\ 8^2]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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