Question 332828
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Let *[tex \Large x] represent the first integer.  Then *[tex \Large x\ +\ 1] is the next consecutive integer, *[tex \Large x\ +\ 2] is the one after that, and so on.


If the second and fourth total 48, then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ 1\ +\ x\ +\ 3\ =\ 48]


Solve for *[tex \Large x] and then count to get the next three numbers.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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