Question 332805
<font face="Garamond" size="+2">


1 cannot be the only solution.  All quadratics have 2 solutions.  The Fundamental Theorem of Algebra says it, I believe it, that settles it.  Hence, the other must be 1 also.  If *[tex \Large \alpha] is a solution of a polynomial equation, then *[tex \Large x\ -\ \alpha] must be a factor of the polynomial.  Having two solutions equal to 1, you must have two factors equal to *[tex \Large x\ -\ 1].  Multiply the two factors and put the result in standard form.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
</font>