<PRE><B>Question 332684</B>

sum of squares of two numbers is
a^2 + b^2 = 90
differnce between two numbers
a - b = 6
then
a = 6 + b
(6 + b)^2 + b^2 = 90
36 + 12b + 2b^2 = 90
2b^2 + 12b - 54 = 0
b^2 + 6b - 27 = 0  (factoring)
b^2+9b -3b -27 =0
b(b+9) -3(b+9)
(b+9)(b-3)
b=-9,3since we have to take the positive number b=3
a=6+3=9
therefore the two numbers are 3and 9</PRE>