Question 332641
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You have a couple of things going on here that are a problem.


In the first place, you didn't follow the instructions for submitting questions on this site.  All you did is put down a function definition (incorrectly as will be seen) without giving any explanation of what you want, what is giving you difficulty, what you have tried, or even the rest of the instructions for the problem.  Please note, this is Algebra.com, NOT the Psychic Hot Line.


In the second place, even though you labeled your relation as a function, it is not a function.  In order to be a function, any given value of the independent variable in the domain of the relation must map to one and only one value of the dependent variable.  The way you have this relation stated, any value of *[tex \Large x\ >\ 3] has a relation value of either *[tex \Large -x] or *[tex \Large 2].  Therefore, not a function.


If you still need help, repost this with a correct function definition, a statement of what you are trying to accomplish, and show the work you have done so far with an explanation of what is giving you difficulty.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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