Question 332622
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Well, you did the math, but at some point you weren't doing the <i>right</i> math.  First let's clear up what looks like a misconception on your part.


Not sure if this is exactly what you meant, but this is what you said:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{22.09}\ +\ \sqrt{7.84}\ =\ \sqrt{29.93}]


Not true.  In general,


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{a}\ +\ \sqrt{b}\ \neq\ \sqrt{a\ +\ b}]


Although, I don't think this is what you really meant because you should never have gotten to the point where you were adding two radicals when you were simply trying to find the distance between two points.


The next thing that is hokey is that you have 7.84, which is 2.8 squared which looks like you subtracted the y coordinate of the first point from the x coordinate of the second point -- oops!


What you should have done:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d\ =\ sqrt{(x_1\ -\ x_2)^2\ +\ (y_1\ -\ y_2)^2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d\ =\ sqrt{\left((-6.8)\ -\ (-2.1)\right)^2\ +\ \left((0.7)\ -\ (-6.2)\right)^2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d\ =\ sqrt{\left(-4.7\right)^2\ +\ \left(6.9\right)^2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d\ =\ sqrt{22.09\ +\ 47.61}]


You good to go from here?


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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