Question 332576
{{{sqrt(7a)+5*sqrt(175a^3)}}}
Factor inside the 2nd radical to reveal the perfect squares
{{{sqrt(7a)+5*sqrt(7*25a^2a)}}}
Extract those squares
{{{sqrt(7a)+5*5*a*sqrt(7a)}}}
{{{sqrt(7a) + 25a*sqrt(7a)}}}
We can't just add them as like terms because of the 25a, but we can
Factor out {{{sqrt(7a)}}}
{{{sqrt(7a)(1 + 25a)}}}
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response to student comment
You have to factor out {{{sqrt(7a)}}}, not 7a, & write it {{{sqrt(7a)(1 + 25a)}}}