<PRE><B>Question 332439</B>
a rectangular area is to enclosed by a fence then divided down the middle by 
another piece of fence then divided by another piece of fence .
if 3600 metres of fence is available, find the maximum area that can be enclosed
:
From the description I see something like this
______
|_|_|_|; 3 enclosed areas
:
2L + 4W = 3600
Simplify, divide by 2
L + 2W = 1800
L = (1800-2W)
:
A = L*W
Replace L with (1800-2W)
A = W(1800-2W)
A quadratic equation
A = -2W^2 + 1800W
Max area occurs at axis of symmetry which is
W = {{{(-1800)/(2*-2)}}}
W = {{{(-1800)/(-4)}}}
W = 450 m, width for max area
:
Find L
L = 1800-2(450)
L = 900 m, length for max area
:
Find max area
900 * 450 = 405,000 sq/m is max area
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