Question 38286
{{{ x^2+7x+9=0 }}}
this is in the form
ax^2 + bx + c = 0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
this will find the roots at the points (r(1), 0) and (r(2),0)
{{{x = (-7 +- sqrt( 7^2-4*1*9 ))/(2*1) }}}
{{{x = (-7 +- sqrt( 13 ))/2 }}}
{{{ graph( 300, 300, -10, 10, -10, 10, x^2 + 7x + 9) }}}