Question 332393
<font face="Garamond" size="+2">


Let *[tex \Large b] represent the measure of the long leg, and let *[tex \Large c] be the measure of the hypotenuse.


Pythagoras says:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ c^2\ -\ b^2\ =\ 60^2]


But we also know that


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ c\ =\ b\ +\ 20]


so:



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (b\ +\ 20)^2\ -\ b^2\ =\ 60^2]


Just solve for *[tex \Large b]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
</font>