Question 332342
It's a quadratic in w^2
Sub x for w^2 and solve it with the quadratic eqn.
Then, each of the 2 solutions = w^2
Take the sq root of each of them.
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Solve for x, which is w^2
*[invoke solve_quadratic_equation 1,-18,-2]
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w^2 = 9 ± sqrt(83)
{{{w = sqrt(9 + sqrt(83))}}} =~ 18.1104
{{{w = sqrt(9 - sqrt(83))}}} =~ 0.1104
{{{w = -sqrt(9 + sqrt(83))}}} =~ -18.1104
{{{w = -sqrt(9 - sqrt(83))}}} =~ -0.1104