Question 332363
If an object is in free fall, the sequence 16, 48, 80, ... represents the distance in feet that the object falls during the first second, during the second second, during the third second, and so on. How far will the object fall during the first 6 seconds? 
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{{{s = at^2/2}}}
16 = a/2 --> a = 32
48 = a*4/2 = 2a --> a = 24
80 = a*9/2 = 4.5a --> a = 32
The acceleration is not constant, so no solution is possible without additional info.
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If the 2nd entry is 64 instead of 48, then the acceleration would be 32 ft/sec/sec, which is apx the Earth's gravitational acceleration.
Then for 6 seconds s = 16*36/2 = 288 feet.