Question 38330
Solve:
{{{3x/(4x-1) = 1/x}}} Cross-multiply.
{{{3x^2 = 4x-1}}} Subtract (4x-1) from both sides.
{{{3x^2-4x+1 = 0}}} Factor.
{{{(3x-1)(x-1) = 0}}} Apply the zero products principle.
{{{3x-1 = 0}}} and/or{{{x-1 =0}}}
If {{{3x-1 = 0}}} then {{{3x = 1}}} and {{{x = 1/3}}}
If {{{x-1 = 0}}} then {{{x = 1}}}
Roots are:
{{{x = 1/3}}}
{{{x = 1}}}