Question 332233
It turns out that this system has an infinite number of solutions. Basically one equation is just the other in a different form. So to solve this "system", we just need to solve for one variable. So what the book did was solve for 'y' (in either equation). 



So take {{{2x-8y=2}}} and solve for x to get {{{2x=8y+2}}} ----> {{{x=(8y+2)/2}}} ----> {{{x=4y+1}}}



So every 'x' coordinate of the solution is simply equal to 4 times the y coordinate plus one.



So recall that any solution of a system is of the form (x,y) and we know that {{{x=4y+1}}}, this means that the solution is (4y+1,y)




Note: there are other ways to display the solution, but you essentially get the same thing.