Question 332112
Factor:
{{{98a^4-72b^2}}} First, factor 2.
{{{2(49a^4-36b^2)}}} Now for some creative factoring:
{{{2((7a^2)^2-(6b)^2)}}} Now we have the difference of two squares in the parentheses and the difference of two squares is factorable thus:
{{{A^2-B^2 = (A+B)(A-B)}}} so we can apply this to your problem by letting {{{A = 7a^2}}} and {{{B = 6b}}}.
{{{2((7a^2)^2-(6b)^2) = highlight(2((7a^2+6b)(7a^2-6b)))}}}