Question 332015
{{{2 * log(4,x) + 3 * log(8,x) = 10}}}
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need to put both logs in same base, choose one base does not matter

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{{{log(8,x)=log(4,x)/log(4,8)}}}  
also {{{log(4,8)=log(2,8)/log(2,4)=log(2,2)^3/log(2,2)^2=3/2}}}

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so... 
{{{log(8,x)=log(4,x)/(3/2)=2/3*log(4,x)}}} 
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subtituting

{{{2 * log(4,x) + 3 * log(8,x) = 2* log(4,x) +2*log(4,x) =4*log(4,x)= 10}}}
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{{{log(4,x)=10/4=5/2}}}
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{{{4^(log(4,x))=4^(5/2)}}}

remember that {{{a^(log(a,x))=x}}}

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x={{{4^(5/2)= (2^(2))^(5/2)=2^5 =32}}}