Question 331931
Seat the n women around the table in (n-1)! ways.  The n men are then seated in the n spaces between the women in n! ways.

Thus, there are {{{n!(n-1)!}}} ways to seat the men and women alternating.

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Tie each married couple together and pretend they are one person.

We can seat them in (n-1)! ways. Now, since each couple can be switched around in 2 ways, there are 2^n ways to arrange all of them

So, there are {{{(n-1)!*2^n}}} ways to arrange the couples with the women sitting with their husbands.