Question 38304
Find the slopes of the assymptotes of the hyperbola with equation {{{x^2/64 - y^2/36=1}}} 
The hyperbola is horizontal, so the slope is b/a ....
a=8
b=6
and the center point is (0,0)
Use point-slope form: {{{y - yp = m(x - xp)}}} where yp and xp are points
{{{y - 0 = (6/8)(x - 0)}}} and {{{y - 0 = (-6/8)(x - 0)}}}
{{{y = (3/4)x}}} and {{{y = -(3/4)x}}}