Question 331950
Find the three consecutive even numbers such that sum of the first and the last numbers exceeds the second number by 10
..
let the numbers be x,x+2,x+4
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x+x+4 = x+2+10
2x+4 = x+12
2x-x 12-4
x=8
..
the numbers are 8,10,12
CHECK
8+12= 10+10