Question 331886
x^2-3x+2=0

a=1,b=-3,c=2
{{{x1=(-b+sqrt(b^2-4*a*c))/2a}}}
{{{x1=(-(-3)+sqrt((3)^2-4*1*2))/2}}}
{{{x1=(+3+sqrt(1))/2
x1= 2
..
{{{X2= (+3-sqrt(1))/2
x2=1
...

y^2+y=6
y^2+y-6=0
a=1b=1c=-6
{{{y1=(-b+sqrt(b^2-4*a*c))/2a}}}

y1=-1+sqrt(1+24)/2
y1=-1+5/2
y1=+2

..
y2= -1-sqrt(1+24)/2
y2=-6/2
y2=-3